What is the domain of (sqrt(x))/(2(sqrt(x))^2-5) ?

The domain of (sqrt(x))/(2(sqrt(x))^2-5) is 0 5/2

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domain of (sqrt(x))/(2(sqrt(x))^2-5)

domain

\frac{x}{2 ( x ) ^{2} - 5}

0 \leq x < \frac{5}{2} or x > \frac{5}{2}

Interval Notation

[0, \frac{5}{2}) \cup (\frac{5}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{5}{2}

Combine real regions and undefined points for final function domain

0 \leq x < \frac{5}{2} or x > \frac{5}{2}

f (x) = lo g_{10} (x) - 0.3

y = x^{2} - 25

\frac{2 x ^{2} - 12 x + 19}{x ^{2} - 6 x + 9}

y - 343 = - \frac{4}{7} (x - 64)

10 x - 6 y = - 4

What is the domain of (sqrt(x))/(2(sqrt(x))^2-5) ?
The domain of (sqrt(x))/(2(sqrt(x))^2-5) is 0<= x< 5/2 \lor x> 5/2