What is the inverse of f(x)= 1/2 (x-1)^3 ?

The inverse of f(x)= 1/2 (x-1)^3 is \sqrt[3]{2}\sqrt[3]{x}+1

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inverse of f(x)= 1/2 (x-1)^3

inverse

f (x) = \frac{1}{2} (x - 1)^{3}

Solution steps

y = \frac{1}{2} (x - 1)^{3}

Replace

x

with

y

x = \frac{1}{2} (y - 1)^{3}

Solve for

y, x = \frac{1}{2} (y - 1)^{3}

x + 2 - 5

f (x) = lo g_{2} (x^{2})

f (x) = \frac{2 x + 6}{x + 4}

\frac{x ^{2}}{x + 3}

f (x) = x^{2} + x + 1

What is the inverse of f(x)= 1/2 (x-1)^3 ?
The inverse of f(x)= 1/2 (x-1)^3 is \sqrt[3]{2}\sqrt[3]{x}+1