What is the domain of g(x)=(sqrt(x))/(9x^2+8x-1) ?

The domain of g(x)=(sqrt(x))/(9x^2+8x-1) is 0 1/9

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domain of g(x)=(sqrt(x))/(9x^2+8x-1)

domain

g (x) = \frac{x}{9 x ^{2} + 8 x - 1}

0 \leq x < \frac{1}{9} or x > \frac{1}{9}

Interval Notation

[0, \frac{1}{9}) \cup (\frac{1}{9}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{1}{9}, x = - 1

Combine real regions and undefined points for final function domain

0 \leq x < \frac{1}{9} or x > \frac{1}{9}

5 x + y = 4

\frac{x ^{2} - 4 x - 5}{x ^{2} - 1}

f (x) = \frac{1}{2} sin (\frac{x}{2}) + \frac{1}{2}

f (x) = \frac{( 2 x - 5 ) ( 2 x + 5 )}{x ^{2}}

(- P, 0), (0, - R)

What is the domain of g(x)=(sqrt(x))/(9x^2+8x-1) ?
The domain of g(x)=(sqrt(x))/(9x^2+8x-1) is 0<= x< 1/9 \lor x> 1/9