What is the domain of sqrt((25-x^2)(x+1)) ?

The domain of sqrt((25-x^2)(x+1)) is x<=-5\lor-1<= x<= 5

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domain of sqrt((25-x^2)(x+1))

domain

(25 - x^{2}) (x + 1)

x \leq - 5 or - 1 \leq x \leq 5

Interval Notation

(- \infty, - 5] \cup [- 1, 5]

Solution steps

Find non-negative values for radicals:

x \leq - 5 or - 1 \leq x \leq 5

The function domain

x \leq - 5 or - 1 \leq x \leq 5

\frac{x ^{2} - 9}{x - 1}

f (x) = \frac{x ^{2}}{x ^{2} + 3}

f (x) = x^{2} - 3 x + 4

f (x) = \frac{x}{6 x + 2}

What is the domain of sqrt((25-x^2)(x+1)) ?
The domain of sqrt((25-x^2)(x+1)) is x<=-5\lor-1<= x<= 5