What is the critical x^3-x^2-5x+7 ?

The critical x^3-x^2-5x+7 is x=-1,x= 5/3

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critical x^3-x^2-5x+7

critical points

x^{3} - x^{2} - 5 x + 7

x = - 1, x = \frac{5}{3}

Solution steps

x^{3} - x^{2} - 5 x + 7

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = \frac{5}{3}

Identify critical points not in

f (x)

domain

Domain of

x^{3} - x^{2} - 5 x + 7 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = \frac{5}{3}

f (x) = x^{3} - 6 x^{2} - 15 x + 8

f (x) = 3 x^{4} - 6 x^{2} + 7

- 2 x + y = 1

\frac{2 x + 4}{7}

8 x + 4 y = 16