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Popular >

range of f(x)=5x^2+9

Solution

range

f (x) = 5 x^{2} + 9

Solution

f (x) \geq 9

+1

Interval Notation

[9, \infty)

Solution steps

Vertex of

5 x^{2} + 9 :

Minimum

(0, 9)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 5,

Vertex

(x_{v}, y_{v}) = (0, 9)

f (x) \geq 9

Popular Examples

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f (x) = \frac{1}{2} e^{x + 3} - 4

domain of f(x)=3x(x+3)(x-5)domain

f (x) = 3 x (x + 3) (x - 5)

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2 sin (\frac{2 π θ}{3})

domain of f(x)=(sqrt(x^2-25))/(x-5)domain

f (x) = \frac{x ^{2} - 25}{x - 5}

Frequently Asked Questions (FAQ)

What is the range of f(x)=5x^2+9 ?
The range of f(x)=5x^2+9 is f(x)>= 9