What is the range of (3x)/(8x-3) ?

The range of (3x)/(8x-3) is f(x) 3/8

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range of (3x)/(8x-3)

range

\frac{3 x}{8 x - 3}

f (x) < \frac{3}{8} or f (x) > \frac{3}{8}

Interval Notation

(- \infty, \frac{3}{8}) \cup (\frac{3}{8}, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{3 x}{8 x - 3}

Inverse of

\frac{3 x}{8 x - 3} : \frac{3 x}{8 x - 3}

\frac{3 x}{8 x - 3}

Find the domain of each inverse function

Domain of

\frac{3 x}{8 x - 3} : x < \frac{3}{8} or x > \frac{3}{8}

Combine the intervals

f (x) < \frac{3}{8} or f (x) > \frac{3}{8}

- 5 x - 4 y = - 8

sin (2.8 x + 0.9) + 0.3

f (x) = \frac{1}{x - 2}

y = - 3 x

f (x) = \frac{x ^{3}}{x - 3}

What is the range of (3x)/(8x-3) ?
The range of (3x)/(8x-3) is f(x)< 3/8 \lor f(x)> 3/8