What is the inverse of f(x)=((4x-1))/(2x+9) ?

The inverse of f(x)=((4x-1))/(2x+9) is (-1-9x)/(2(-2+x))

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inverse of f(x)=((4x-1))/(2x+9)

inverse

f (x) = \frac{( 4 x - 1 )}{2 x + 9}

\frac{- 1 - 9 x}{2 ( - 2 + x )}

Solution steps

y = \frac{4 x - 1}{2 x + 9}

Replace

x

with

y

x = \frac{4 y - 1}{2 y + 9}

Solve for

y, x = \frac{4 y - 1}{2 y + 9}

\frac{- 1 - 9 x}{2 ( - 2 + x )}

f (x) = \frac{x ^{2} + 3 x - 28}{x ^{2} - 16}

5 x^{3} - 1

f (x) = 5 + lo g_{2} (x + 5)

9 x + 3 y = 12

f (x) = \frac{5 x}{9}

What is the inverse of f(x)=((4x-1))/(2x+9) ?
The inverse of f(x)=((4x-1))/(2x+9) is (-1-9x)/(2(-2+x))