What is the extreme f(x)=-x^3+9x^2-2 ?

The extreme f(x)=-x^3+9x^2-2 is Minimum(0,-2),Maximum(6,106)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x^3+9x^2-2

extreme points

f (x) = - x^{3} + 9 x^{2} - 2

Minimum (0, - 2), Maximum (6, 106)

Solution steps

f^{'} (x) = - 3 x^{2} + 18 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 6,

Decreasing

: 6 < x < \infty

Plug

x = 0

into

- x^{3} + 9 x^{2} - 2 : - 2

Minimum (0, - 2)

Plug

x = 6

into

- x^{3} + 9 x^{2} - 2 : 106

Maximum (6, 106)

Minimum (0, - 2), Maximum (6, 106)

f (x) = x^{2} - 10 x + 16

f (x) = 4 x^{2} + x + 5

f (x) = \frac{x - 4}{3 x - x ^{2}}

- \frac{1}{t} - \frac{1}{9} t

f (x) = 5 - x

What is the extreme f(x)=-x^3+9x^2-2 ?
The extreme f(x)=-x^3+9x^2-2 is Minimum(0,-2),Maximum(6,106)