What is the critical f(x)=x^4-4x^3 ?

The critical f(x)=x^4-4x^3 is x=0,x=3

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critical f(x)=x^4-4x^3

critical points

f (x) = x^{4} - 4 x^{3}

x = 0, x = 3

Solution steps

x^{4} - 4 x^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 3

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 4 x^{3} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 3

f (x) = (x + 4)^{3}

(3, - 6), (5, 8)

sec (x)

\frac{x ^{2}}{x ^{2} - 16}

y = \frac{5}{x}