What is the line (0,14),(12.07,0) ?

The line (0,14),(12.07,0) is y=-1.15990…x+14

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line (0,14),(12.07,0)

line

(0, 14), (12.07, 0)

y = - 1.15990 \dots x + 14

Solution steps

Find the line

y = mx + b

passing through

(0, 14)

(12.07, 0)

Compute the slope

(0, 14), (12.07, 0) : m = - 1.15990 \dots

Compute the

y

intercept:

b = 14

Construct the line equation

y = mx + b

where

m = - 1.15990 \dots

and

b = 14

y = - 1.15990 \dots x + 14

y = 0. 3^{x}

\frac{x ^{2} + 4 x + 6}{x + 2}

x + 6 y = - 12

f (x) = x^{3} - 3 x^{2} + 7

f (x) = x^{\frac{5}{3}} - 5 x^{\frac{2}{3}}

What is the line (0,14),(12.07,0) ?
The line (0,14),(12.07,0) is y=-1.15990…x+14