What is the asymptotes of f(x)=((x-5))/(2x+1) ?

The asymptotes of f(x)=((x-5))/(2x+1) is Vertical: x=-1/2 ,Horizontal: y= 1/2

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asymptotes of f(x)=((x-5))/(2x+1)

asymptotes

f (x) = \frac{( x - 5 )}{2 x + 1}

Vertical : x = - \frac{1}{2}, Horizontal : y = \frac{1}{2}

Solution steps

Vertical asymptotes of

\frac{x - 5}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{x - 5}{2 x + 1} : y = \frac{1}{2}

Slant Asymptotes of

\frac{x - 5}{2 x + 1} :

None

Vertical : x = - \frac{1}{2}, Horizontal : y = \frac{1}{2}

f (x) = 2 x^{3} + 7 x^{2} + 4 x - 5

(9 - 6 x) e^{x}

7 x - 7

f (x) = x^{2} + 6 x + 2

(1, 4), (- 2, - 8)

What is the asymptotes of f(x)=((x-5))/(2x+1) ?
The asymptotes of f(x)=((x-5))/(2x+1) is Vertical: x=-1/2 ,Horizontal: y= 1/2