What is the extreme f(x)=x^4-4x^2-4 ?

The extreme f(x)=x^4-4x^2-4 is Minimum(-sqrt(2),-8),Maximum(0,-4),Minimum(sqrt(2),-8)

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extreme f(x)=x^4-4x^2-4

extreme points

f (x) = x^{4} - 4 x^{2} - 4

Minimum (- 2, - 8), Maximum (0, - 4), Minimum (2, - 8)

Solution steps

f^{'} (x) = 4 x^{3} - 8 x

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{4} - 4 x^{2} - 4 : - 8

Minimum (- 2, - 8)

Plug

x = 0

into

x^{4} - 4 x^{2} - 4 : - 4

Maximum (0, - 4)

Plug

x = 2

into

x^{4} - 4 x^{2} - 4 : - 8

Minimum (2, - 8)

Minimum (- 2, - 8), Maximum (0, - 4), Minimum (2, - 8)

y = x^{2} - 5 x

f (x) = - 36 - x^{2}

(1, 2), (3, 7)

(x - 2)^{3} + 1

f (x) = \frac{- x ^{2} - 3 x + 3}{x + 1}

What is the extreme f(x)=x^4-4x^2-4 ?
The extreme f(x)=x^4-4x^2-4 is Minimum(-sqrt(2),-8),Maximum(0,-4),Minimum(sqrt(2),-8)