What is the inverse of f(x)= 1/4 x^3-2 ?

The inverse of f(x)= 1/4 x^3-2 is cube root of 4x+8

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inverse of f(x)= 1/4 x^3-2

inverse

f (x) = \frac{1}{4} x^{3} - 2

Solution steps

y = \frac{1}{4} x^{3} - 2

Replace

x

with

y

x = \frac{1}{4} y^{3} - 2

Solve for

y, x = \frac{1}{4} y^{3} - 2

3 cos (4 x)

y = 1 - \frac{x}{5}

f (x) = \frac{x - 3}{2 x ^{2} + 10 x}

f (x) = - 4 x^{3} + 5

What is the inverse of f(x)= 1/4 x^3-2 ?
The inverse of f(x)= 1/4 x^3-2 is cube root of 4x+8