What is the domain of 1/(x^2-4x-5) ?

The domain of 1/(x^2-4x-5) is x 5

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domain of 1/(x^2-4x-5)

domain

\frac{1}{x ^{2} - 4 x - 5}

x < - 1 or - 1 < x < 5 or x > 5

Interval Notation

(- \infty, - 1) \cup (- 1, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 1

The function domain

x < - 1 or - 1 < x < 5 or x > 5

f (x) = - \frac{3}{2} x - 5

f (x) = 8 x

\frac{9 x ^{2} - 9}{3 x ^{2} + 12 x + 12}

f (x) = 2^{x}

What is the domain of 1/(x^2-4x-5) ?
The domain of 1/(x^2-4x-5) is x<-1\lor-1<x<5\lor x>5