What is the domain of g(x)=sqrt(3x-1)+5 ?

The domain of g(x)=sqrt(3x-1)+5 is x>= 1/3

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domain of g(x)=sqrt(3x-1)+5

domain

g (x) = 3 x - 1 + 5

x \geq \frac{1}{3}

Interval Notation

[\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{3}

The function domain

x \geq \frac{1}{3}

f (x) = - 6 x + 24

f (x) = 3 x^{2} + x - 5

f (x) = - 4 - x^{2}

f (x) = 3 x^{3} + 1

f (x) = 3 \cdot 5^{x - 8} + 17

What is the domain of g(x)=sqrt(3x-1)+5 ?
The domain of g(x)=sqrt(3x-1)+5 is x>= 1/3