What is the critical x^6(x-4)^5 ?

The critical x^6(x-4)^5 is x=0,x= 24/11 ,x=4

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critical x^6(x-4)^5

critical points

x^{6} (x - 4)^{5}

x = 0, x = \frac{24}{11}, x = 4

Solution steps

x^{6} (x - 4)^{5}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{24}{11}, x = 4

Identify critical points not in

f (x)

domain

Domain of

x^{6} (x - 4)^{5} : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{24}{11}, x = 4

y = - 3 x + 2

f (x) = \frac{7 x + 1}{x ^{2} - 4}

f (x) = e^{4 x - 6}

f (x) = \frac{2 x ^{2} + x - 5}{x ^{4} + 9}

\frac{x ^{2} - 7}{x - 4}