What is the domain of f(x)=(sqrt(t-4))/(3t-24) ?

The domain of f(x)=(sqrt(t-4))/(3t-24) is 4 8

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domain of f(x)=(sqrt(t-4))/(3t-24)

domain

f (x) = \frac{t - 4}{3 t - 24}

4 \leq t < 8 or t > 8

Interval Notation

[4, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 4

Find undefined (singularity) points:

t = 8

Combine real regions and undefined points for final function domain

4 \leq t < 8 or t > 8

f (x) = \frac{( - 1 )}{x ^{3}}

f (x) = \frac{1}{x + 3}

f (x) = \frac{2}{3} x + 2

f (x) = \frac{1 - 4 x}{5 + x}

\frac{x ^{2} - 9}{4 x ^{2}}

What is the domain of f(x)=(sqrt(t-4))/(3t-24) ?
The domain of f(x)=(sqrt(t-4))/(3t-24) is 4<= t<8\lor t>8