What is the inverse of f(x)=x^2-4x-3,x<= 2 ?

The inverse of f(x)=x^2-4x-3,x<= 2 is 2+sqrt(x+7),2-sqrt(x+7)

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inverse of f(x)=x^2-4x-3,x<= 2

inverse

f (x) = x^{2} - 4 x - 3, x \leq 2

2 + x + 7, 2 - x + 7

Solution steps

y = x^{2} - 4 x - 3

Replace

x

with

y

x = y^{2} - 4 y - 3

Solve for

y, x = y^{2} - 4 y - 3

2 + x + 7, 2 - x + 7

f (x) = \frac{4 x ^{2} - x}{x ^{2} - 1}

f (x) = - 2^{x}

\frac{x}{1 + x}

ln (x) + 6

x^{2} - 10 x + 24

What is the inverse of f(x)=x^2-4x-3,x<= 2 ?
The inverse of f(x)=x^2-4x-3,x<= 2 is 2+sqrt(x+7),2-sqrt(x+7)