What is the domain of 9+sqrt(x^2-4) ?

The domain of 9+sqrt(x^2-4) is x = 2

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domain of 9+sqrt(x^2-4)

domain

9 + x^{2} - 4

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

2 sin (3 x - π)

y = sin (\frac{1}{2}) (x + \frac{π}{4})

f (x) = \frac{x - 4}{- 4 x - 16}

f (x) = \frac{1}{x - 3} + 4

f (x) = 2 sin (\frac{2}{3} x - \frac{π}{6})

What is the domain of 9+sqrt(x^2-4) ?
The domain of 9+sqrt(x^2-4) is x<=-2\lor x>= 2