What is the domain of y= x/(x^2+9) ?

The domain of y= x/(x^2+9) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y= x/(x^2+9)

domain

y = \frac{x}{x ^{2} + 9}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x + 1}{x ^{2}} - 1

f (x) = 3 x^{4} - 6 x^{3}

f (x) = \frac{x}{5} - 3

x^{2} - 12 x + 46

- x^{2} - 1 x + 2

What is the domain of y= x/(x^2+9) ?
The domain of y= x/(x^2+9) is -infinity <x<infinity