What is the inverse of f(x)=log_{2}(x-3)+1 ?

The inverse of f(x)=log_{2}(x-3)+1 is 2^{x-1}+3

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inverse of f(x)=log_{2}(x-3)+1

inverse

f (x) = lo g_{2} (x - 3) + 1

2^{x - 1} + 3

Solution steps

y = lo g_{2} (x - 3) + 1

Replace

x

with

y

x = lo g_{2} (y - 3) + 1

Solve for

y, x = lo g_{2} (y - 3) + 1

2^{x - 1} + 3

(x - 3) x

\frac{x}{( x - 1 ) ( x + 5 )}

\frac{2}{x ^{2} - 2 x - 3}

f (x) = \frac{7 x + 6}{x - 3}

f (x) = \frac{x - 2}{4 x - 16}

What is the inverse of f(x)=log_{2}(x-3)+1 ?
The inverse of f(x)=log_{2}(x-3)+1 is 2^{x-1}+3