What is the domain of (x^2+7x)/(5x^2-1) ?

The domain of (x^2+7x)/(5x^2-1) is x 1/(sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (x^2+7x)/(5x^2-1)

domain

\frac{x ^{2} + 7 x}{5 x ^{2} - 1}

x < - \frac{1}{5} or - \frac{1}{5} < x < \frac{1}{5} or x > \frac{1}{5}

Interval Notation

(- \infty, - \frac{1}{5}) \cup (- \frac{1}{5}, \frac{1}{5}) \cup (\frac{1}{5}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{5}, x = - \frac{1}{5}

The function domain

x < - \frac{1}{5} or - \frac{1}{5} < x < \frac{1}{5} or x > \frac{1}{5}

f (x) = - \frac{1}{2} x^{2} + 4 x - 2

f (x) = \frac{5}{( x - 2 ) ^{2}}

f (x) = 6 - 2 x^{2}

f (x) = 5^{x - 2}

f (x) = - 2 x - 7

What is the domain of (x^2+7x)/(5x^2-1) ?
The domain of (x^2+7x)/(5x^2-1) is x<-1/(sqrt(5))\lor-1/(sqrt(5))<x< 1/(sqrt(5))\lor x> 1/(sqrt(5))