What is the domain of f(x)=sqrt(x^2+x+3) ?

The domain of f(x)=sqrt(x^2+x+3) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+x+3)

domain

f (x) = x^{2} + x + 3

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 5 - x^{2}

f (x) = \frac{x ^{2} + 1}{4}

- x - 3

\frac{4 s + 12}{s ^{2} + 8 s + 16}

y = ln ∣ x ∣

What is the domain of f(x)=sqrt(x^2+x+3) ?
The domain of f(x)=sqrt(x^2+x+3) is -infinity <x<infinity