What is the domain of f(x)=sqrt(x)+8 ?

The domain of f(x)=sqrt(x)+8 is x>= 0

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domain of f(x)=sqrt(x)+8

domain

f (x) = x + 8

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

- \frac{1}{2} x^{2} + 4 x - 2

f (x) = 2 (x - 1) - 1

f (x) = \frac{1}{x - 6}

f (x) = x + 7

f (x) = \frac{5 x - 3}{x - 1}