What is the domain of f(x)=(sqrt(4-x))(sqrt(x^2-1)) ?

The domain of f(x)=(sqrt(4-x))(sqrt(x^2-1)) is x<=-1\lor 1<= x<= 4

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domain of f(x)=(sqrt(4-x))(sqrt(x^2-1))

domain

f (x) = (4 - x) (x^{2} - 1)

x \leq - 1 or 1 \leq x \leq 4

Interval Notation

(- \infty, - 1] \cup [1, 4]

Solution steps

Find non-negative values for radicals:

x \leq - 1 or 1 \leq x \leq 4

The function domain

x \leq - 1 or 1 \leq x \leq 4

f (x) = \frac{x + 5}{x ^{2} + 3}

f (x) = x - \frac{2}{x}

- 6 p^{2} + 300 p

lo g_{6} (2 x)

\frac{2 x - 5}{x - 3}

What is the domain of f(x)=(sqrt(4-x))(sqrt(x^2-1)) ?
The domain of f(x)=(sqrt(4-x))(sqrt(x^2-1)) is x<=-1\lor 1<= x<= 4