What is the domain of y=sqrt(x^2-1) ?

The domain of y=sqrt(x^2-1) is x = 1

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domain of y=sqrt(x^2-1)

domain

y = x^{2} - 1

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

\frac{1}{x + 2}

\frac{6 x + 9}{x - 1}

7 x + 2 y = 14

f (x) = \frac{1}{6} x - 1

4 (x + 3)^{2} - 100

What is the domain of y=sqrt(x^2-1) ?
The domain of y=sqrt(x^2-1) is x<=-1\lor x>= 1