What is the inverse of f(x)=7x^{3/2}-4 ?

The inverse of f(x)=7x^{3/2}-4 is cube root of (x^2+8x+16)/(49)

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inverse of f(x)=7x^{3/2}-4

inverse

f (x) = 7 x^{\frac{3}{2}} - 4

Solution steps

y = 7 x^{\frac{3}{2}} - 4

Replace

x

with

y

x = 7 y^{\frac{3}{2}} - 4

Solve for

y, x = 7 y^{\frac{3}{2}} - 4

f (x) = 3 x^{2} + 9 x - 3

f (x) = (x + 1)^{2}

(0, 1), (- 5, - 3)

f (x) = 9 (x - 3)^{\frac{2}{3}}

\frac{1}{x + 7}

What is the inverse of f(x)=7x^{3/2}-4 ?
The inverse of f(x)=7x^{3/2}-4 is cube root of (x^2+8x+16)/(49)