What is the domain of f(x)=(10x^2+35x)/(49x^2-28x+4) ?

The domain of f(x)=(10x^2+35x)/(49x^2-28x+4) is x 2/7

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domain of f(x)=(10x^2+35x)/(49x^2-28x+4)

domain

f (x) = \frac{10 x ^{2} + 35 x}{49 x ^{2} - 28 x + 4}

x < \frac{2}{7} or x > \frac{2}{7}

Interval Notation

(- \infty, \frac{2}{7}) \cup (\frac{2}{7}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{2}{7}

The function domain

x < \frac{2}{7} or x > \frac{2}{7}

f (x) = ln (x^{2} - x - 20)

4 x - 3 y = 12

f (x) = \frac{3 x ^{2} + 6}{x ^{2} - 2 x - 3}

f (x) = \frac{x + 2}{5 x - 1}

f (x) = x^{4} - 3 x^{2}

What is the domain of f(x)=(10x^2+35x)/(49x^2-28x+4) ?
The domain of f(x)=(10x^2+35x)/(49x^2-28x+4) is x< 2/7 \lor x> 2/7