What is the inverse of f(x)=\sqrt[3]{x^2-5x-4} ?

The inverse of f(x)=\sqrt[3]{x^2-5x-4} is (5+sqrt(4x^3+41))/2 ,(5-sqrt(4x^3+41))/2

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inverse of f(x)=\sqrt[3]{x^2-5x-4}

inverse

\frac{5 + 4 x ^{3} + 41}{2}, \frac{5 - 4 x ^{3} + 41}{2}

Solution steps

Replace

x

with

y

Solve for

\frac{5 + 4 x ^{3} + 41}{2}, \frac{5 - 4 x ^{3} + 41}{2}

y = 7 x - 8, (5, - 2)

f (x) = \frac{3}{2 x - 5}

2 + x - 1

\frac{2}{x}

f (x) = x \cdot 35 + 5

What is the inverse of f(x)=\sqrt[3]{x^2-5x-4} ?
The inverse of f(x)=\sqrt[3]{x^2-5x-4} is (5+sqrt(4x^3+41))/2 ,(5-sqrt(4x^3+41))/2