What is the domain of f(x)=(x^2+x-12)/(x-3) ?

The domain of f(x)=(x^2+x-12)/(x-3) is x 3

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domain of f(x)=(x^2+x-12)/(x-3)

domain

f (x) = \frac{x ^{2} + x - 12}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

(- 1, 4), (2, 2)

f (x) = - \frac{3}{x + 1} - 1

f (x) = \frac{x + 3}{x - 2}

x + 2 y - 4 = 0

f (x) = \frac{5}{x - 7}

What is the domain of f(x)=(x^2+x-12)/(x-3) ?
The domain of f(x)=(x^2+x-12)/(x-3) is x<3\lor x>3