What is the asymptotes of f(x)=((24x^2+6x))/((2x+1)) ?

The asymptotes of f(x)=((24x^2+6x))/((2x+1)) is Vertical: x=-1/2 ,Slant: y=12x-3

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asymptotes of f(x)=((24x^2+6x))/((2x+1))

asymptotes

f (x) = \frac{( 24 x ^{2} + 6 x )}{( 2 x + 1 )}

Vertical : x = - \frac{1}{2}, Slant : y = 12 x - 3

Solution steps

Vertical asymptotes of

\frac{24 x ^{2} + 6 x}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{24 x ^{2} + 6 x}{2 x + 1} :

None

Slant Asymptotes of

\frac{24 x ^{2} + 6 x}{2 x + 1} : y = 12 x - 3

Vertical : x = - \frac{1}{2}, Slant : y = 12 x - 3

f (x) = \frac{3}{4 + x}

4 x + 1

y = - 15

f (x) = x + 3

What is the asymptotes of f(x)=((24x^2+6x))/((2x+1)) ?
The asymptotes of f(x)=((24x^2+6x))/((2x+1)) is Vertical: x=-1/2 ,Slant: y=12x-3