What is the domain of f(x)=((3x+2))/(sqrt(x^2-7x)) ?

The domain of f(x)=((3x+2))/(sqrt(x^2-7x)) is x 7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=((3x+2))/(sqrt(x^2-7x))

domain

f (x) = \frac{( 3 x + 2 )}{x ^{2} - 7 x}

x < 0 or x > 7

Interval Notation

(- \infty, 0) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 7

Find undefined (singularity) points:

x = 7, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 7

f (x) = \frac{5}{2 5 x + 6}

f (x) = 2 x^{2} + 10 x + 1

3 x - 2 y = 8

6 X - Y + 20 = 0

f (x) = \frac{2 x + 9}{3 x - 2}

What is the domain of f(x)=((3x+2))/(sqrt(x^2-7x)) ?
The domain of f(x)=((3x+2))/(sqrt(x^2-7x)) is x<0\lor x>7