What is the inverse of f(x)=6+\sqrt[3]{x} ?

The inverse of f(x)=6+\sqrt[3]{x} is x^3-18x^2+108x-216

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inverse of f(x)=6+\sqrt[3]{x}

inverse

x^{3} - 18 x^{2} + 108 x - 216

Solution steps

Replace

x

with

y

Solve for

x^{3} - 18 x^{2} + 108 x - 216

f (x) = 5

f (x) = (13 - t)^{\frac{1}{4}}

\frac{5 x}{x ^{2} + 3 x - 4}

f (x) = x ln (4 x)

x^{2} - 5 x + 3

What is the inverse of f(x)=6+\sqrt[3]{x} ?
The inverse of f(x)=6+\sqrt[3]{x} is x^3-18x^2+108x-216