What is the inverse of y= 1/2 x^2 ?

The inverse of y= 1/2 x^2 is sqrt(2)sqrt(x),-sqrt(2)sqrt(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y= 1/2 x^2

inverse

y = \frac{1}{2} x^{2}

2 x, - 2 x

Solution steps

y = \frac{1}{2} x^{2}

Replace

x

with

y

x = \frac{1}{2} y^{2}

Solve for

y, x = \frac{1}{2} y^{2}

2 x, - 2 x

y = x^{2} - x^{4}

sin (2 x + 1)

f (x) = (2 x) - \frac{3}{5}

f (x) = 5 + x^{2} - 4 x

\frac{2 x}{3 x - 8}

What is the inverse of y= 1/2 x^2 ?
The inverse of y= 1/2 x^2 is sqrt(2)sqrt(x),-sqrt(2)sqrt(x)