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Popular >

extreme f(x)=2x^2+6x+10

Solution

extreme points

f (x) = 2 x^{2} + 6 x + 10

Solution

Minimum (- \frac{3}{2}, \frac{11}{2})

Solution steps

f^{'} (x) = 4 x + 6

Find intervals:

Decreasing

: - \infty < x < - \frac{3}{2},

Increasing

: - \frac{3}{2} < x < \infty

Plug

x = - \frac{3}{2}

into

2 x^{2} + 6 x + 10 : \frac{11}{2}

Minimum (- \frac{3}{2}, \frac{11}{2})

Popular Examples

inverse of f(x)= x/(4x-3)inverse

f (x) = \frac{x}{4 x - 3}

inverse of f(x)=3-2x^5 inverse

f (x) = 3 - 2 x^{5}

f (x) = x - 4

distance (-3,2),(5,4)distance

(- 3, 2), (5, 4)

inverse of f(x)=(2x+1)/(3x-2)inverse

f (x) = \frac{2 x + 1}{3 x - 2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2+6x+10 ?
The extreme f(x)=2x^2+6x+10 is Minimum(-3/2 , 11/2)