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Popular >

midpoint (-1,3),(1,-2)

Solution

midpoint

(- 1, 3), (1, - 2)

Solution

(0, \frac{1}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 1, 3), (x_{2}, y_{2}) = (1, - 2)

= (\frac{1 - 1}{2}, \frac{- 2 + 3}{2})

Refine

= (0, \frac{1}{2})

Popular Examples

inflection f(x)=10x^3-3x^5 inflection points

f (x) = 10 x^{3} - 3 x^{5}

domain of x^2 domain

x^{2}

distance (1,6),(-7,0)distance

(1, 6), (- 7, 0)

domain of f(x)=5+e^{2x}domain

f (x) = 5 + e^{2 x}

f (x) = x^{2} - 4

Frequently Asked Questions (FAQ)

What is the midpoint (-1,3),(1,-2) ?
The midpoint (-1,3),(1,-2) is (0, 1/2)