What is the critical 2/(x^2)+ln(x) ?

The critical 2/(x^2)+ln(x) is x=2

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critical 2/(x^2)+ln(x)

critical points

\frac{2}{x ^{2}} + ln (x)

x = 2

Solution steps

\frac{2}{x ^{2}} + ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{2}{x ^{2}} + ln (x) : x > 0

\frac{2}{x ^{2}} + ln (x)

is not defined at

x = - 2, x = 0

, therefore:

x = 2

x^{2} + 4

m = 7, (0, 0)

f (x) = - 2 x^{3} + 3 x - 1

2 cos (x) - sin (2 x)

(- 4, 1), (2, - 3)