What is the extreme f(x)=x-(64x)/(x+4) ?

The extreme f(x)=x-(64x)/(x+4) is Maximum(-20,-100),Minimum(12,-36)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x-(64x)/(x+4)

extreme points

f (x) = x - \frac{64 x}{x + 4}

Maximum (- 20, - 100), Minimum (12, - 36)

Solution steps

f^{'} (x) = 1 - \frac{256}{( x + 4 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 20,

Decreasing

: - 20 < x < - 4,

Decreasing

: - 4 < x < 12,

Increasing

: 12 < x < \infty

Plug

x = - 20

into

x - \frac{64 x}{x + 4} : - 100

Maximum (- 20, - 100)

Plug

x = 12

into

x - \frac{64 x}{x + 4} : - 36

Minimum (12, - 36)

Maximum (- 20, - 100), Minimum (12, - 36)

m = 3, (- 6, 7)

f (x) = 4^{x + 2} + 6

(2, 1), (5, 3)

f (x) = 2 x^{2} - 8

f (x) = \frac{10 - 2 x ^{2}}{x ^{2} - 4}

What is the extreme f(x)=x-(64x)/(x+4) ?
The extreme f(x)=x-(64x)/(x+4) is Maximum(-20,-100),Minimum(12,-36)