What is the inverse of f(x)=((x+19))/(x-17) ?

The inverse of f(x)=((x+19))/(x-17) is (19+17x)/(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=((x+19))/(x-17)

inverse

f (x) = \frac{( x + 19 )}{x - 17}

\frac{19 + 17 x}{x - 1}

Solution steps

y = \frac{x + 19}{x - 17}

Replace

x

with

y

x = \frac{y + 19}{y - 17}

Solve for

y, x = \frac{y + 19}{y - 17}

\frac{19 + 17 x}{x - 1}

f (x) = \frac{2}{( x - 1 ) ^{3}}

f (x) = - 2 x^{2} + 12 x - 20

7 x + 5 y = 1

(\frac{5}{3}, - \frac{16}{9}), (- \frac{1}{3}, \frac{19}{9})

f (x) = - 3 cos (3 x)

What is the inverse of f(x)=((x+19))/(x-17) ?
The inverse of f(x)=((x+19))/(x-17) is (19+17x)/(x-1)