What is the inverse of f(x)=-(x-1)^2-3 ?

The inverse of f(x)=-(x-1)^2-3 is sqrt(-x-3)+1,-sqrt(-x-3)+1

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inverse of f(x)=-(x-1)^2-3

inverse

f (x) = - (x - 1)^{2} - 3

- x - 3 + 1, - - x - 3 + 1

Solution steps

y = - (x - 1)^{2} - 3

Replace

x

with

y

x = - (y - 1)^{2} - 3

Solve for

y, x = - (y - 1)^{2} - 3

- x - 3 + 1, - - x - 3 + 1

f (x) = \frac{e ^{x}}{e ^{x} - 4}

f (x) = \frac{13 x ^{3}}{7 x ^{2} + 6}

2 y - 4 x = - 16

- x^{2} - 13 x - 12

(0, 2), (3, 1)

What is the inverse of f(x)=-(x-1)^2-3 ?
The inverse of f(x)=-(x-1)^2-3 is sqrt(-x-3)+1,-sqrt(-x-3)+1