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Popular >

f(x)=2x^2+3x+1

Solution

f (x) = 2 x^{2} + 3 x + 1

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - \frac{1}{8}

X Intercepts : (- \frac{1}{2}, 0), (- 1, 0), Y Intercepts : (0, 1)

Vertex : Minimum (- \frac{3}{4}, - \frac{1}{8})

Inverse : \frac{- 3 + 8 x + 1}{4}, \frac{- 3 - 8 x + 1}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{1}{8}, \infty)

Solution steps

Domain of

2 x^{2} + 3 x + 1 : - \infty < x < \infty

Range of

2 x^{2} + 3 x + 1 : f (x) \geq - \frac{1}{8}

Axis interception points of

2 x^{2} + 3 x + 1 :

X Intercepts

: (- \frac{1}{2}, 0), (- 1, 0),

Y Intercepts

: (0, 1)

Vertex of

2 x^{2} + 3 x + 1 :

Minimum

(- \frac{3}{4}, - \frac{1}{8})

Inverse of

2 x^{2} + 3 x + 1 : \frac{- 3 + 8 x + 1}{4}, \frac{- 3 - 8 x + 1}{4}

Popular Examples

domain of y=ln(x-1)+e^{x^2-3}+(x^2-4)^{5/3}domain

y = ln (x - 1) + e^{x^{2} - 3} + (x^{2} - 4)^{\frac{5}{3}}

f (a) = ln (a)

f (x) = (\frac{3}{4})^{x}

y^2=4(x+4)^3,0<= x<= 2,y>0

y^{2} = 4 (x + 4)^{3}, 0 \leq x \leq 2, y > 0

y = - 2 cos (x)

Frequently Asked Questions (FAQ)

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