What is the inverse of g(x)=(-x+4)/(8+3x) ?

The inverse of g(x)=(-x+4)/(8+3x) is (4-8x)/(3x+1)

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inverse of g(x)=(-x+4)/(8+3x)

inverse

g (x) = \frac{- x + 4}{8 + 3 x}

\frac{4 - 8 x}{3 x + 1}

Solution steps

y = \frac{- x + 4}{8 + 3 x}

Replace

x

with

y

x = \frac{- y + 4}{8 + 3 y}

Solve for

y, x = \frac{- y + 4}{8 + 3 y}

\frac{4 - 8 x}{3 x + 1}

3 x - y = 6

π - arccos (2 x + 1)

f (x) = \frac{x ^{2}}{x - 5}

f (x) = - x^{3} + 12 x^{2} - 45 x + 2

f (x) = 2 - 4 x

What is the inverse of g(x)=(-x+4)/(8+3x) ?
The inverse of g(x)=(-x+4)/(8+3x) is (4-8x)/(3x+1)