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Popular >

extreme f(x)=ln(3-4x^2)

Solution

extreme points

f (x) = ln (3 - 4 x^{2})

Solution

Maximum (0, ln (3))

Solution steps

f^{'} (x) = - \frac{8 x}{3 - 4 x ^{2}}

Find intervals:

Increasing

: - \frac{3}{2} < x < 0,

Decreasing

: 0 < x < \frac{3}{2}

Plug

x = 0

into

ln (3 - 4 x^{2}) : ln (3)

Maximum (0, ln (3))

Popular Examples

extreme f(x)=2x^3+3x^2+1 extreme points

f (x) = 2 x^{3} + 3 x^{2} + 1

critical (2x-x^2)e^x critical points

(2 x - x^{2}) e^{x}

domain of f(x)=(sqrt(x+3))/(x-3)domain

f (x) = \frac{x + 3}{x - 3}

domain of (x^2-2x-3)/x domain

\frac{x ^{2} - 2 x - 3}{x}

inverse of f(x)=3+sqrt(8+x)inverse

f (x) = 3 + 8 + x

Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(3-4x^2) ?
The extreme f(x)=ln(3-4x^2) is Maximum(0,ln(3))