What is the inverse of 3/(\frac{2){2+x}+2} ?

The inverse of 3/(\frac{2){2+x}+2} is (6-6x)/(2x-3)

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inverse of 3/(\frac{2){2+x}+2}

inverse

\frac{3}{\frac{2}{2 + x} + 2}

\frac{6 - 6 x}{2 x - 3}

Solution steps

y = \frac{3}{\frac{2}{2 + x} + 2}

Replace

x

with

y

x = \frac{3}{\frac{2}{2 + y} + 2}

Solve for

y, x = \frac{3}{\frac{2}{2 + y} + 2}

\frac{6 - 6 x}{2 x - 3}

f (x) = 49 - x^{2}

f (x) = 3 sin (\frac{1}{2} x)

f (x) = 5 x + 4 y = - 20

f (x) = 2 sin (x)

f (x) = - 16 t^{2} + 64 t

What is the inverse of 3/(\frac{2){2+x}+2} ?
The inverse of 3/(\frac{2){2+x}+2} is (6-6x)/(2x-3)