What is the inverse of f(x)=(3x+2)/(4x+3)+7 ?

The inverse of f(x)=(3x+2)/(4x+3)+7 is (23-3x)/(4x-31)

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inverse of f(x)=(3x+2)/(4x+3)+7

inverse

f (x) = \frac{3 x + 2}{4 x + 3} + 7

\frac{23 - 3 x}{4 x - 31}

Solution steps

y = \frac{3 x + 2}{4 x + 3} + 7

Replace

x

with

y

x = \frac{3 y + 2}{4 y + 3} + 7

Solve for

y, x = \frac{3 y + 2}{4 y + 3} + 7

\frac{23 - 3 x}{4 x - 31}

f (x) = \frac{x ^{2}}{6 - x}

\frac{x + 2}{x + 3}

f (x) = ln (x) + 7

f (x) = x^{2} - 9

f (x) = 4 csc (4 x)

What is the inverse of f(x)=(3x+2)/(4x+3)+7 ?
The inverse of f(x)=(3x+2)/(4x+3)+7 is (23-3x)/(4x-31)