What is the inverse of f(x)=(3x-2)/(x+5) ?

The inverse of f(x)=(3x-2)/(x+5) is (-2-5x)/(x-3)

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inverse of f(x)=(3x-2)/(x+5)

inverse

f (x) = \frac{3 x - 2}{x + 5}

\frac{- 2 - 5 x}{x - 3}

Solution steps

y = \frac{3 x - 2}{x + 5}

Replace

x

with

y

x = \frac{3 y - 2}{y + 5}

Solve for

y, x = \frac{3 y - 2}{y + 5}

\frac{- 2 - 5 x}{x - 3}

(x - 1)^{2}, x \geq 1

f (x) = \frac{1 + x}{x ^{2} - 1}

3 x = 9

f (x) = \frac{1}{( x + 4 )}

f (x) = \frac{x ^{2} + 6 x - 8}{x - 8}

What is the inverse of f(x)=(3x-2)/(x+5) ?
The inverse of f(x)=(3x-2)/(x+5) is (-2-5x)/(x-3)