What is the critical x^4-8x^3+10 ?

The critical x^4-8x^3+10 is x=0,x=6

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critical x^4-8x^3+10

critical points

x^{4} - 8 x^{3} + 10

x = 0, x = 6

Solution steps

x^{4} - 8 x^{3} + 10

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 6

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 8 x^{3} + 10 : - \infty < x < \infty

All critical points are in domain

x = 0, x = 6

8 x + 2 y = - 10

f (x) = \frac{- 3}{2 x - 1}

2 x^{2} + 5

- sin (x - \frac{π}{6})

f (x) = ln (e^{x} - 1) - ln (2) - 1