What is the domain of sqrt((x+3)(-x^2+16)) ?

The domain of sqrt((x+3)(-x^2+16)) is x<=-4\lor-3<= x<= 4

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domain of sqrt((x+3)(-x^2+16))

domain

(x + 3) (- x^{2} + 16)

x \leq - 4 or - 3 \leq x \leq 4

Solution steps

Find non-negative values for radicals:

x \leq - 4 or - 3 \leq x \leq 4

The function domain

x \leq - 4 or - 3 \leq x \leq 4

f (x) = 1.0106 x

f (x) = \frac{- 5}{x + 6}

f (x) = \frac{x - 3}{x - 10}

f (x) = - 3

What is the domain of sqrt((x+3)(-x^2+16)) ?
The domain of sqrt((x+3)(-x^2+16)) is x<=-4\lor-3<= x<= 4