What is the domain of f(x)=(x^3+3x^2+x+3)/(x+1) ?

The domain of f(x)=(x^3+3x^2+x+3)/(x+1) is x -1

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domain of f(x)=(x^3+3x^2+x+3)/(x+1)

domain

f (x) = \frac{x ^{3} + 3 x ^{2} + x + 3}{x + 1}

x < - 1 or x > - 1

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = 6 x - 6

f (x) = \frac{2 x}{( x + 4 ) ^{3}}

f

f (x) = x^{3} - 31 x + 30

f (x) = \frac{5}{x + 8}

What is the domain of f(x)=(x^3+3x^2+x+3)/(x+1) ?
The domain of f(x)=(x^3+3x^2+x+3)/(x+1) is x<-1\lor x>-1